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1 Unit AS 1: Pure Mathematics

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Question 162

Show that exln⁡5=5xe^{x\ln5}=5^xexln5=5x and hence solve e(2x−1)ln⁡5=125e^{(2x-1)\ln5}=125e(2x−1)ln5=125.

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1 Unit AS 1: Pure Mathematics Questions

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