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1 Unit AS 1: Pure Mathematics

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Question 187

In triangle PQRPQRPQR, PQ=10PQ=10PQ=10 cm, ∠PRQ=30∘\angle PRQ=30^\circ∠PRQ=30∘ and ∠PQR=45∘\angle PQR=45^\circ∠PQR=45∘. Find PRPRPR.

[3]
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1 Unit AS 1: Pure Mathematics Questions

  1. A Level
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