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1 Unit AS 1: Pure Mathematics

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Question 25

Consider 6cos⁡2x=4−sin⁡x6\cos^2x=4-\sin x6cos2x=4−sinx.

a.

Show that this becomes 6sin⁡2x−sin⁡x−2=06\sin^2x-\sin x-2=06sin2x−sinx−2=0.

[2]
b.

Hence solve for 0∘≤x<360∘0^\circ\leq x<360^\circ0∘≤x<360∘.

[5]
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1 Unit AS 1: Pure Mathematics Questions

  1. A Level
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