1.4 Trigonometry

67%

a.

Show that the equation

2\sin^2 x = 7\cos x + 5

Can be written in the form

2\cos^2 x + 7\cos x + 3 = 0

[3]

b.

Hence solve, for $\leq x < 360^\circ$ , the equation,

2\sin^2 x = 7\cos x + 5

[5]

67%

a.

Show that the equation

2\sin^2 x = 7\cos x + 5

Can be written in the form

2\cos^2 x + 7\cos x + 3 = 0

[3]

b.

Hence solve, for $\leq x < 360^\circ$ , the equation,

2\sin^2 x = 7\cos x + 5

[5]

1.4 Trigonometry Questions