By writing sin3A \sin 3A\,sin3A as sin(2A+A)\sin(2A + A)sin(2A+A), show that sin3A=3sinA−4sin3A\sin 3A = 3\sin A - 4\sin^3 Asin3A=3sinA−4sin3A.
Solve, for 0≤A≤1800 \leq A \leq 1800≤A≤180, the equation,
3sinA−4sin3A=0.85 3\sin A - 4\sin^3 A = 0.85 3sinA−4sin3A=0.85Give your answers to 1 decimal place.
221 exam-style questions on CCEA A Level Maths 3.4 Trigonometry (A-level only), covering 3.4.1 Trigonometry (A-level only), 3.4.2 Trigonometry (A-level only), 3.4.3 Trigonometry (A-level only), 3.4.4 Trigonometry (A-level only), 3.4.5 Trigonometry (A-level only), 3.4.6 Trigonometry (A-level only), 3.4.7 Trigonometry (A-level only), and 3.4.8 Trigonometry (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.