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2.2.4 Kinematics

2.2.4 Kinematics

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Question 18

At 09:00 hiker A A\,A has position vector (6i−2j)(6\mathbf{i} - 2\mathbf{j})(6i−2j) km and moves with constant velocity (−2i+4j)(-2\mathbf{i} + 4\mathbf{j})(−2i+4j) km h−1\text{h}^{-1}h−1. Hiker B B\,B has position vector (11i+3j)(11\mathbf{i} + 3\mathbf{j})(11i+3j) km and moves with constant velocity (2i+2j)(2\mathbf{i} + 2\mathbf{j})(2i+2j) km h−1\text{h}^{-1}h−1.

a.

Find the relative displacement of hiker A A\,A from hiker B B\,B after t t\,t hours.

[6]
b.

Find the time when A A\,A is due west of BBB.

[2]
c.

Find the time, after 09:00, when the hikers are exactly 290 \sqrt{290}\,290​ km apart.

[6]
Markscheme

2.2.4 Kinematics Questions

  1. A Level
  2. /Maths
  3. /2.2.4 Kinematics

29 exam-style questions on CCEA A Level Maths 2.2.4 Kinematics. Each one has a worked solution and a mark scheme showing where the marks go.

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