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1.7 Integration

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Question 24

A curve has equation y=f(x)y = f(x)y=f(x), where

f′′(x)=12x5+4x,x>0 f''(x) = \frac{12}{\sqrt{x^5}} + 4x, \quad x > 0 f′′(x)=x5​12​+4x,x>0

The point P(1,−2)P(1, -2)P(1,−2) lies on the curve.

Given that f′(x)=1f'(x) = 1f′(x)=1 at point PPP,

a.

find the equation of the normal at PPP, writing your answer in the form y=mx+cy = mx + cy=mx+c, where mmm and ccc are constants,

[3]
b.

find f(x)f(x)f(x).

[5]

1.7 Integration Questions

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