A curve has equation y=f(x)y = f(x)y=f(x), where
f′′(x)=12x5+4x,x>0 f''(x) = \frac{12}{\sqrt{x^5}} + 4x, \quad x > 0 f′′(x)=x512+4x,x>0The point P(1,−2)P(1, -2)P(1,−2) lies on the curve.
Given that f′(x)=1f'(x) = 1f′(x)=1 at point PPP,
find the equation of the normal at PPP, writing your answer in the form y=mx+cy = mx + cy=mx+c, where mmm and ccc are constants,
find f(x)f(x)f(x).