The monthly rate of increase of a fish population in a reservoir is equal to 1.5% of the current population. P P\,P is the population in hundreds and t t\,t is the time in months.
Write down a differential equation for this relationship.
Show that P=Ae0.015tP = Ae^{0.015t}P=Ae0.015t where A A\,A is a constant.
Given that the initial population is 800 fish. Find the population after 2 years (24 months), to the nearest whole number.
363 exam-style questions on CCEA A Level Maths 3.6 Integration (A-level only), covering 3.6.1 Integration (A-level only), 3.6.2 Integration (A-level only), 3.6.3 Integration (A-level only), 3.6.4 Integration (A-level only), 3.6.5 Integration (A-level only), 3.6.6 Integration (A-level only), and 3.6.7 Integration (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.