Given that
5x+3(x−1)(3x+1)2≡Ax−1+B3x+1+C(3x+1)2 \frac{5x+3}{(x-1)(3x+1)^2} \equiv \frac{A}{x-1} + \frac{B}{3x+1} + \frac{C}{(3x+1)^2} (x−1)(3x+1)25x+3≡x−1A+3x+1B+(3x+1)2Cfind the values of the constants AAA, BBB and CCC.
Hence find the exact value of
∫235x+3(x−1)(3x+1)2 dx \int_{2}^{3} \frac{5x+3}{(x-1)(3x+1)^2} \,\mathrm{d}x ∫23(x−1)(3x+1)25x+3dxgiving your answer in the form plnq+rp \ln q + rplnq+r where ppp, qqq and rrr are rational numbers.