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1.5.5 Exponentials and logarithms

Hard
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Question 4

For x>0x>0x>0, prove that log⁡a(xk)=klog⁡ax\log_a(x^k)=k\log_axloga​(xk)=kloga​x.

[4]
Markscheme

1.5.5 Exponentials and logarithms Questions

  1. A Level
  2. /Maths
  3. /1.5.5 Exponentials and logarithms

8 exam-style questions on CCEA A Level Maths 1.5.5 Exponentials and logarithms. Each one has a worked solution and a mark scheme showing where the marks go.

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