Using logarithm laws, prove that logax=12logax\displaystyle \log_a\sqrt{x}=\frac12\log_axlogax=21logax for x>0x>0x>0.
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Markscheme
1.5.5 Exponentials and logarithms Questions
8 exam-style questions on CCEA A Level Maths 1.5.5 Exponentials and logarithms. Each one has a worked solution and a mark scheme showing where the marks go.