The movement of a precision robotic arm across a flat surface is defined by the parametric relationship
x=6cos2y0≤x≤6,0≤y≤π4 x = 6 \cos 2y \quad 0 \le x \le 6, \quad 0 \le y \le \frac{\pi}{4} x=6cos2y0≤x≤6,0≤y≤4πwhere xxx is the horizontal position in millimetres and yyy is the control angle in radians.
Find dxdy\frac{dx}{dy}dydx in terms of yyy.
Hence show that
dydx=k36−x2 \frac{dy}{dx} = \frac{k}{\sqrt{36-x^2}} dxdy=36−x2kwhere kkk is a constant to be found.
A specific calibration point P(a,b)P(a, b)P(a,b) lies on the path of the arm. Given that
find the exact values of aaa and bbb.