The point P(−6,−4)P(-6, -4)P(−6,−4) lies on the curve with equation y=f(x)y = f(x)y=f(x), x∈Rx \in \mathbb{R}x∈R.
Find the coordinates of the point to which PPP is mapped when the curve with equation y=f(x)y = f(x)y=f(x) is transformed to the curve with equation:
y=f(3x)y = f(3x)y=f(3x)
y=2f(x+2)y = 2f(x + 2)y=2f(x+2)
y=∣f(x)∣y = |f(x)|y=∣f(x)∣
