A precision thermal probe uses a linear scaling function HHH to map a raw voltage vvv to a temperature reading H(v)H(v)H(v), defined by:
H(v)=11v−214H(v) = \frac{11v - 21}{4}H(v)=411v−21
A technician identifies a specific voltage where the probe's output is identical to the output of the inverse scaling function H−1H^{-1}H−1 applied to that same voltage.
Solve the equation:
H(v)=H−1(v)H(v) = H^{-1}(v)H(v)=H−1(v)
Select your answer from the options below:
v=−3v = -3v=−3
v=1v = 1v=1
v=3v = 3v=3
v=7v = 7v=7
