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2.3 M: Probability

2.3 M: Probability

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Question 37

The events A A\,A and B B\,B are such that P(A)=1120\displaystyle P(A) = \frac{11}{20}P(A)=2011​, P(A∩B)=320\displaystyle P(A \cap B) = \frac{3}{20}P(A∩B)=203​, P(A∣B)=38\displaystyle P(A|B) = \frac{3}{8}P(A∣B)=83​. Find

a.

P(B)P(B)P(B)

[3]
b.

P(A∪B)P(A \cup B)P(A∪B)

[3]
c.

P(B∣A′)P(B|A')P(B∣A′)

[3]
Markscheme

2.3 M: Probability Questions

  1. A Level
  2. /Maths
  3. /2.3 M: Probability

198 exam-style questions on AQA A Level Maths 2.3 M: Probability, covering 2.3.1 Mutually exclusive and independent events, 2.3.2 Conditional probability (A-level only), 2.3.3 Modelling with probability (A-level only), and 2.3 M: Probability. Each one has a worked solution and a mark scheme showing where the marks go.

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