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1.7.5 Geometric sequences and series (A-level only)

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Question 21

The first three terms of a geometric series are (2k−2)(2k-2)(2k−2), (k+3)(k+3)(k+3), and k k\,k respectively, where k k\,k is a positive constant.

a.

Show that k2−8k−9=0k^2 - 8k - 9 = 0k2−8k−9=0.

[4]
b.

Hence show that k=9k = 9k=9.

[2]
c.

Find the common ratio.

[2]
d.

The sum to infinity of the series.

[2]

1.7.5 Geometric sequences and series (A-level only) Questions

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