The equation for the combustion of ethanol, C2H5OH\text{C}_2\text{H}_5\text{OH}C2H5OH, is shown below: $\text{C}_2\text{H}_5\text{OH(l)} + 3\text{O}_2\text{(g)} \rightarrow 2\text{CO}_2\text{(g)} + 3\text{H}_2\text{O(l)}$ Enthalpy changes of formation are shown in the table: $\begin{array}{|c|c|c|c|} \hline \text{Substance} & \text{C}_2\text{H}_5\text{OH(l)} & \text{CO}_2\text{(g)} & \text{H}2\text{O(l)} \\ \hline \Delta{\text{f}}H\text{ / kJ mol}^{-1} & -277 & -394 & -286 \\ \hline \end{array}$ Calculate the enthalpy of combustion, in kJ mol−1\text{kJ mol}^{-1}kJ mol−1, for ethanol.