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Physical chemistry

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Question 2

The equation for the combustion of propan-1-ol, C3H7OH\text{C}_3\text{H}_7\text{OH}C3​H7​OH, is shown below: \

\text{C}_3\text{H}_7\text{OH(l)} + 4.5\text{O}_2\text{(g)} \rightarrow 3\text{CO}_2\text{(g)} + 4\text{H}_2\text{O(l)}{\char"24}$ Enthalpy changes of formation are shown in the table: \

\begin{array}{|c|c|c|c|} \hline \text{Substance} & \text{C}_3\text{H}_7\text{OH(l)} & \text{CO}_2\text{(g)} & \text{H}2\text{O(l)} \ \hline \Delta{\text{f}}H\text{ / kJ mol}^{-1} & -318 & -394 & -286 \ \hline \end{array}{\char"24}$

Calculate the enthalpy of combustion, in kJ mol−1\text{kJ mol}^{-1}kJ mol−1, for propan-1-ol.

[3]

Physical chemistry Questions

  1. A Level
  2. /Chemistry
  3. /Physical chemistry