Compounds V, W, X and Y are isomers with the molecular formula C6H12O2\text{C}_6\text{H}_{12}\text{O}_2C6H12O2.
Isomers V and W are carboxylic acids with formulas that can be written as C5H11COOH\text{C}_5\text{H}_{11}\text{COOH}C5H11COOH.
Give an equation for the reaction of C5H11COOH\text{C}_5\text{H}_{11}\text{COOH}C5H11COOH with sodium hydrogencarbonate.
Isomer V has an asymmetric carbon atom. Deduce a possible structure of V.
Isomer W has four peaks in its 1H{}^1\text{H}1H NMR spectrum. Deduce the structure of W and deduce the integration ratio for its four peaks.
Isomer X has three singlets with integration ratio 1:2:91:2:91:2:9 in its 1H{}^1\text{H}1H NMR spectrum. Deduce the structure of X and explain why the peaks in its 1H{}^1\text{H}1H NMR spectrum are singlets.
The table below shows information about the peaks in the 1H{}^1\text{H}1H NMR spectrum of isomer Y:
| Chemical shift δ\deltaδ / ppm | Integration ratio | Splitting pattern |
|---|---|---|
| 1.97 | 3 | singlet |
| 1.45 | 9 | singlet |