In the presence of a strong base, 2-bromopropane reacts with hydroxide ions via an E2 E2\,E2 elimination mechanism to form propene, water, and bromide ions:
HO−+H−CH2−CH(Br)−CH3→H2O+CH2=CH−CH3+Br− \text{HO}^- + \text{H}-\text{CH}_2-\text{CH}(\text{Br})-\text{CH}_3 \rightarrow \text{H}_2\text{O} + \text{CH}_2=\text{CH}-\text{CH}_3 + \text{Br}^- HO−+H−CH2−CH(Br)−CH3→H2O+CH2=CH−CH3+Br−
Which curly arrow does not appear in the mechanism of this reaction?
Arrow A
Arrow B
Arrow C
Arrow D