Which is the concentration of KOH(aq)\text{KOH(aq)}KOH(aq), in mol dm−3\text{mol dm}^{-3}mol dm−3, that has pH=14.10\text{pH} = 14.10pH=14.10?
Kw=1.00×10−14 mol2 dm−6K_{\text{w}} = 1.00 \times 10^{-14} \text{ mol}^2 \text{ dm}^{-6}Kw=1.00×10−14 mol2 dm−6 at 25 ∘C25\ ^\circ\text{C}25 ∘C.
−1.00-1.00−1.00
7.94×10−157.94 \times 10^{-15}7.94×10−15
1.26×10141.26 \times 10^{14}1.26×1014
1.261.261.26
