What is the pH of a 0.28 mol dm-3 solution of sodium hydroxide at 298 K?
(Kw=1.0×10−14 mol2 dm−6K_{\text{w}} = 1.0 \times 10^{-14}\text{ mol}^2\text{ dm}^{-6}Kw=1.0×10−14 mol2 dm−6 at 298 K)
0.550.550.55
13.4513.4513.45
13.7213.7213.72
14.5514.5514.55
