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22:[["$","$L31",null,{"feature":"flashcards"}],"$L32",["$","$L33",null,{"href":"/igcse/physics/edexcel/change-of-state/flashcards","label":"Change of state","subjectCode":"igcse_physics","surface":"flashcards"}],["$","$L34",null,{"runner":["$","div",null,{"className":"min-h-0 flex-1 overflow-hidden bg-background","children":["$","$L35",null,{"decks":[{"id":"eba40ea7-e923-4196-a15d-959f8515b85c","title":"Change of state Flashcards","topicId":"ca81eb6a-cb43-5ef4-b029-2b54ffa42d21","topicSlug":"change-of-state","cards":[{"id":"d3ed6dcd-a13e-471c-913f-ebf9770a80d8","cardType":"basic","points":1,"front":"How are particles arranged in a solid?","back":"

Close together
Regular arrangement (lattice)

","mcqOptions":[{"text":"

Close together
Regular arrangement (lattice)

","correct":true,"explanation":"Solid particles are packed close together in a fixed, regular lattice. They vibrate about fixed positions but do not move freely through the material."},{"text":"

Far apart
Random arrangement

","correct":false,"explanation":"Particles that are far apart and randomly arranged describe a gas. In a solid, particles are close together in a regular arrangement called a lattice."},{"text":"

Close together
Irregular arrangement

","correct":false,"explanation":"Although liquid particles are close together, their arrangement is irregular rather than a lattice. Solid particles are close together in a regular arrangement."},{"text":"

Far apart
Regular arrangement (lattice)

","correct":false,"explanation":"A regular arrangement alone is insufficient because widely spaced particles do not form an ordinary solid. Solid particles are both close together and regularly arranged."}]},{"id":"4e54fd2c-0f71-4165-88d9-d8962e7913d1","cardType":"basic","points":1,"front":"How do particles move in a liquid?","back":"They move around and slide past each other.","mcqOptions":[{"text":"They move around and slide past each other.","correct":true,"explanation":"Liquid particles are not fixed in place. They move around and slide past neighbouring particles, allowing the liquid to flow and change shape."},{"text":"They vibrate around fixed positions.","correct":false,"explanation":"Vibrating about fixed positions describes particle motion in a solid. Liquid particles can move around and slide past each other rather than remaining fixed."},{"text":"They move rapidly in random directions.","correct":false,"explanation":"Rapid motion in random directions is the characteristic model for gas particles. Liquid particles remain close together while moving around and sliding past each other."},{"text":"They remain stationary and fixed together.","correct":false,"explanation":"Liquid particles are in continuous random motion, not completely stationary. They move around and slide past each other, which enables the liquid to flow."}]},{"id":"fc8b6394-4ad5-4cc1-98f4-a7ac8abdd763","cardType":"basic","points":1,"front":"How do particles move in a gas?","back":"Rapidly in random directions.","mcqOptions":[{"text":"Rapidly in random directions.","correct":true,"explanation":"Gas particles have high speeds and move randomly in all directions. Their frequent changes of direction result mainly from collisions with other particles and container walls."},{"text":"Slowly in fixed directions.","correct":false,"explanation":"Slow movement past neighbouring particles is more characteristic of a liquid. Gas particles travel rapidly in random directions between collisions."},{"text":"Rapidly around fixed positions.","correct":false,"explanation":"Vibration about fixed positions describes particles in a solid, where strong forces maintain a lattice. Gas particles instead move rapidly in random directions."},{"text":"Rapidly in regular directions.","correct":false,"explanation":"Gas particles do not all follow a regular common direction, even when a gas flows overall. Their individual motion is rapid and in random directions."}]},{"id":"0fde2808-cceb-4411-a248-73b64a0c01d4","cardType":"basic","points":2,"front":"State the two main effects that adding energy to a system can have.","back":"

Raise the temperature
Cause a change of state

","mcqOptions":[{"text":"

Raise the temperature
Cause a change of state

","correct":true,"explanation":"Added energy can increase particles’ average kinetic energy, raising temperature, or overcome forces between particles and produce a change of state."},{"text":"

Lower the temperature
Cause a change of state

","correct":false,"explanation":"Adding energy does not normally lower a system’s temperature. Its two main effects are raising temperature or supplying the energy needed for a change of state."},{"text":"

Raise the temperature
Cause an increase in mass

","correct":false,"explanation":"Energy transfer does not create matter, so it does not increase mass. Added energy can raise temperature or cause a change of state."},{"text":"

Increase the density
Cause a decrease in volume

","correct":false,"explanation":"Adding energy does not necessarily increase density or decrease volume; heating often causes expansion instead. The main effects are a temperature rise or a change of state."}]},{"id":"bd2e26ee-d056-4b20-909a-b88120eba44c","cardType":"basic","points":2,"front":"Why does temperature remain constant while a substance is melting or boiling?","back":"Energy is used to overcome forces between particles instead of increasing their average kinetic energy.","mcqOptions":[{"text":"Energy is used to overcome forces between particles instead of increasing their average kinetic energy.","correct":true,"explanation":"During melting or boiling, supplied energy weakens or overcomes attractive forces between particles. It does not increase average kinetic energy, so temperature stays constant."},{"text":"Energy is used to increase the speed of particles instead of overcoming their attractive forces.","correct":false,"explanation":"Increasing average kinetic energy would increase temperature, not keep it constant. During a change of state, energy instead overcomes forces between particles."},{"text":"Energy is used to create particles instead of increasing their average kinetic energy.","correct":false,"explanation":"The number of particles does not increase during melting or boiling because no matter is created. Energy overcomes interparticle forces rather than increasing average kinetic energy."},{"text":"Energy is used to reduce forces between particles by decreasing their average kinetic energy.","correct":false,"explanation":"Particles do not lose kinetic energy merely because energy is being added. The supplied energy overcomes forces between particles while average kinetic energy remains constant."}]},{"id":"5e2a0767-9fc1-4b6d-b323-8285a9e97fb9","cardType":"basic","points":3,"front":"Give three differences between evaporation and boiling.","back":"

Evaporation happens only at the surface (Boiling is throughout)
Evaporation occurs below the boiling point
Boiling involves bubbles forming inside the liquid

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Evaporation happens only at the surface (Boiling is throughout)
Evaporation occurs below the boiling point
Boiling involves bubbles forming inside the liquid

","correct":true,"explanation":"Evaporation is a surface process that can occur below boiling point. Boiling occurs throughout the liquid at boiling point and produces bubbles inside it."},{"text":"

Evaporation happens throughout the liquid (Boiling is at the surface)
Evaporation occurs below the boiling point
Boiling involves bubbles forming inside the liquid

","correct":false,"explanation":"This reverses where the processes occur. Evaporation happens only at the surface, whereas boiling occurs throughout the liquid and forms bubbles inside it."},{"text":"

Evaporation happens only at the surface (Boiling is throughout)
Evaporation occurs only at the boiling point
Boiling involves bubbles forming inside the liquid

","correct":false,"explanation":"Evaporation is not restricted to the boiling point; it can occur at temperatures below it. Boiling occurs at boiling point and produces bubbles throughout the liquid."},{"text":"

Evaporation happens only at the surface (Boiling is throughout)
Evaporation occurs below the boiling point
Evaporation involves bubbles forming inside the liquid

","correct":false,"explanation":"Visible bubbles inside the liquid are a feature of boiling, not evaporation. Evaporation occurs only at the surface and can happen below boiling point."}]},{"id":"4c83866b-489d-46de-8a20-9339f958d25c","cardType":"basic","points":1,"front":"What does a plateau (flat section) represent on a heating curve?","back":"A change of state.","mcqOptions":[{"text":"A change of state.","correct":true,"explanation":"A plateau shows that added energy is causing a change of state rather than raising temperature. The energy is used to overcome forces between particles."},{"text":"A rise in temperature.","correct":false,"explanation":"A temperature increase is represented by a sloping section, not a plateau. A flat section shows a change of state occurring at constant temperature."},{"text":"A loss of energy.","correct":false,"explanation":"Cooling would require energy to leave the substance and is not what a plateau on a heating curve signifies. The plateau represents a change of state."},{"text":"A stop in particle motion.","correct":false,"explanation":"Particles are not motionless during a plateau; their average kinetic energy remains constant while their arrangement changes. The flat section represents a change of state."}]},{"id":"76e38d6d-c157-463d-92ea-dcfea42ab0da","cardType":"basic","points":1,"front":"On a heating curve, what does a sloping section indicate about the particles?","back":"Their average kinetic energy is increasing.","mcqOptions":[{"text":"Their average kinetic energy is increasing.","correct":true,"explanation":"A rising temperature means the particles’ average kinetic energy is increasing. On a heating curve, this temperature rise is shown by a sloping section."},{"text":"Their average potential energy is increasing.","correct":false,"explanation":"Potential energy mainly increases during a change of state, represented by a plateau. On a sloping section, rising temperature means average kinetic energy increases."},{"text":"Their average kinetic energy is decreasing.","correct":false,"explanation":"Decreasing average kinetic energy would make temperature fall, contrary to an upward-sloping heating curve. The particles’ average kinetic energy is increasing."},{"text":"Their total number of particles is increasing.","correct":false,"explanation":"Particle number remains constant during ordinary heating because matter is not being created. A sloping section indicates increasing average kinetic energy and temperature."}]},{"id":"856ac168-adf4-4721-82ce-04db104bed22","cardType":"basic","points":1,"front":"Why must the thermometer not touch the bottom of the beaker when heating ice?","back":"The beaker base may be hotter than the substance, leading to an inaccurate reading.","mcqOptions":[{"text":"The beaker base may be hotter than the substance, leading to an inaccurate reading.","correct":true,"explanation":"The heater warms the beaker base directly, so contact with it could make the thermometer measure the base rather than the ice-water mixture’s true temperature."},{"text":"The beaker base may be colder than the substance, leading to an inaccurate reading.","correct":false,"explanation":"The base is heated directly, so it is likely to be hotter, not colder, than the substance. Touching it would therefore produce an inaccurately high temperature reading."},{"text":"The beaker base may be thinner than the substance, leading to an inaccurate reading.","correct":false,"explanation":"The thickness of the beaker base does not determine what the thermometer measures. The problem is that the directly heated base may be hotter than the substance."},{"text":"The beaker base may be cooler than the thermometer, leading to an inaccurate reading.","correct":false,"explanation":"Comparing the base with the thermometer itself is the misconception. The thermometer must measure the substance, while the directly heated base may have a higher temperature."}]},{"id":"6d4a95cb-ce45-4698-ac19-5c411c621dd5","cardType":"basic","points":1,"front":"Define specific heat capacity.","back":"Energy required to change the temperature of 1 kg of a substance by 1 °C.","mcqOptions":[{"text":"Energy required to change the temperature of 1 kg of a substance by 1 °C.","correct":true,"explanation":"Specific heat capacity is the energy needed per kilogram for a one-degree temperature change, linking energy, mass and temperature through $E = mc\\Delta T$."},{"text":"Energy required to change the state of 1 kg of a substance at constant temperature.","correct":false,"explanation":"This defines specific latent heat, where energy changes state without changing temperature. Specific heat capacity concerns changing the temperature of 1 kg by 1 °C."},{"text":"Energy required to change the temperature of 1 g of a substance by 1 °C.","correct":false,"explanation":"Using grams is a common unit mistake. Specific heat capacity is defined for a mass of 1 kg whose temperature changes by 1 °C."},{"text":"Energy required to change the temperature of 1 kg of a substance by 100 °C.","correct":false,"explanation":"The definition uses a temperature change of 1 °C, not 100 °C. Increasing the stated change by a factor of 100 changes the quantity being defined."}]},{"id":"40de06ec-a91d-4713-9ecd-aca41d63481d","cardType":"basic","points":1,"front":"What is the standard unit for specific heat capacity?","back":"J/kg °C","mcqOptions":[{"text":"J/kg °C","correct":true,"explanation":"Specific heat capacity is energy divided by mass and temperature change, so its standard unit is joules per kilogram per degree Celsius."},{"text":"J/kg","correct":false,"explanation":"This is the unit of specific latent heat because it omits temperature change. Specific heat capacity must also be divided by degrees Celsius, giving J/kg °C."},{"text":"J/°C","correct":false,"explanation":"This is the unit of heat capacity for an entire object because it omits mass. Specific heat capacity is measured per kilogram, giving J/kg °C."},{"text":"J kg/°C","correct":false,"explanation":"Multiplying by mass reverses the required relationship. Specific heat capacity is energy divided by both mass and temperature change, so the unit is J/kg °C."}]},{"id":"eba2e1c4-f0da-4318-8c41-47e2ac53166c","cardType":"basic","points":1,"front":"How is electrical energy transferred ($E$) calculated in an SHC experiment?","back":"$$$E = V \\times I \\times t$$","mcqOptions":[{"text":"$$$E = V \\times I \\times t$$","correct":true,"explanation":"Electrical power is $P = VI$, and energy transferred equals power multiplied by time. Combining these relationships gives $E = VIt$."},{"text":"$$$E = V \\times I \\div t$$","correct":false,"explanation":"Dividing by time confuses energy with a rate. Since $VI$ gives power, it must be multiplied by time to obtain energy: $E = VIt$."},{"text":"$$$E = V \\div I \\times t$$","correct":false,"explanation":"Using $V/I$ applies the resistance relationship rather than calculating electrical power. Power is $VI$, so energy transferred over time is $E = VIt$."},{"text":"$$$E = V \\times I \\times t^2$$","correct":false,"explanation":"Squaring time has no basis in the energy calculation and gives incorrect units. Electrical energy is power multiplied by time once, so $E = VIt$."}]},{"id":"b6156afc-b3fe-44fc-9d87-ea17e9c6d78a","cardType":"basic","points":2,"front":"Why does heat loss to the surroundings make the calculated SHC value too large?","back":"Energy is recorded as entering the substance, but some is lost, so the temperature rise ($\\Delta T$) is smaller than expected for that energy.","mcqOptions":[{"text":"Energy is recorded as entering the substance, but some is lost, so the temperature rise ($\\Delta T$) is smaller than expected for that energy.","correct":true,"explanation":"In $c = E/(m\\Delta T)$, the recorded energy is too high relative to the measured temperature rise because some energy escapes. This makes the calculated SHC too large."},{"text":"Energy is recorded as leaving the substance, but some is gained, so the temperature rise ($\\Delta T$) is larger than expected for that energy.","correct":false,"explanation":"The experiment records electrical energy supplied, not energy leaving. Heat loss makes the measured temperature rise smaller, so dividing the recorded energy by $m\\Delta T$ overestimates SHC."},{"text":"Energy is recorded as entering the substance, but some is lost, so the temperature rise ($\\Delta T$) is larger than expected for that energy.","correct":false,"explanation":"Heat loss cannot make the temperature rise larger; it leaves less energy available to heat the substance. The smaller measured $\\Delta T$ makes the calculated SHC too large."},{"text":"Energy is recorded as entering the substance, but some is lost, so the temperature rise ($\\Delta T$) is unchanged for that energy.","correct":false,"explanation":"Assuming no effect on temperature ignores the energy transferred to the surroundings. Heat loss reduces the measured temperature rise, causing $E/(m\\Delta T)$ to overestimate SHC."}]},{"id":"b2928606-3c29-46bc-ba55-22549e5339c6","cardType":"basic","points":3,"front":"List three ways to improve the accuracy of a specific heat capacity investigation.","back":"

Use insulation (and a lid for liquids)
Stir the liquid to ensure uniform temperature
Use oil/thermal paste to improve contact with the heater

","mcqOptions":[{"text":"

Use insulation (and a lid for liquids)
Stir the liquid to ensure uniform temperature
Use oil/thermal paste to improve contact with the heater

","correct":true,"explanation":"Insulation reduces unwanted energy loss, stirring makes the measured temperature representative of the whole liquid, and thermal paste improves energy transfer between the heater and substance."},{"text":"

Use metal fins (and no lid for liquids)
Avoid stirring the liquid during heating
Use an air gap around the heater

","correct":false,"explanation":"Metal fins and an open top increase heat loss, while avoiding stirring causes temperature gradients and an air gap reduces thermal contact. Insulation, stirring and thermal paste improve accuracy."},{"text":"

Use black paint (and a wide lid for liquids)
Heat one side to create varied temperatures
Use water to separate the heater

","correct":false,"explanation":"Black surfaces can increase radiation, deliberately uneven heating makes the thermometer reading unrepresentative, and water may alter the system. Insulation, stirring and thermal paste are appropriate improvements."},{"text":"

Use thin walls (and remove the lid for liquids)
Place the thermometer beside the heater
Use greaseproof paper around the heater

","correct":false,"explanation":"Thin walls and removing the lid increase heat loss, while measuring beside the heater can give a local hot-spot reading. Insulation, stirring and thermal paste reduce these errors."}]}]}],"examCountdown":{"examDate":"2027-05-25","paperLabel":"Paper 1"},"heading":"Change of state","title":"Change of state Flashcards","topbar":{"backHref":"/igcse/physics/edexcel/flashcards"},"topicSidebar":"$L36"}]}],"topicId":"ca81eb6a-cb43-5ef4-b029-2b54ffa42d21","walled":"$L37"}],"$L38","$L39"]