A student investigates the balancing of a metre rule. The experimental setup has a metre rule balanced on a pivot at the 50.0 cm50.0\text{ cm}50.0 cm mark.
The student places object P with its centre at the 15.0 cm15.0\text{ cm}15.0 cm mark. Because object P covers the scale under it, explain briefly how to place this object as accurately as possible so that its centre is exactly at the 15.0 cm15.0\text{ cm}15.0 cm mark.
The distance aaa is the distance between the centre of object P and the pivot. The student places object Q on the other side of the pivot and adjusts its position to balance the rule. The centre of Q is at the 74.5 cm74.5\text{ cm}74.5 cm mark. Determine and state the distance bbb between the centre of object Q and the pivot.
The experiment is repeated for different positions of object P. The results are shown in Table 1.1:
| a/cma / \text{cm}a/cm | b/cmb / \text{cm}b/cm |
|---|---|
| 35.0 | 24.5 |
| 30.0 | 21.1 |
| 25.0 | 17.6 |
| 20.0 | 14.0 |
| 15.0 | 10.6 |
Using the first and last data points in Table 1.1, calculate the gradient GGG of the line of best fit, where aaa is on the yyy-axis and bbb is on the xxx-axis.
The gradient GGG of the graph is equal to the ratio RRR of the masses of P and Q (where R=mPmQR = \frac{m_P}{m_Q}R=mQmP). Record the ratio RRR of the masses. Give your answer to a suitable number of significant figures.
43 exam-style questions on CIE IGCSE Physics 1.5.2a Moment of a force. Each one has a worked solution and a mark scheme showing where the marks go.