A student performs an experiment to determine the focal length fff of a thin converging lens. They measure various object distances uuu and the corresponding image distances vvv, and plot a graph of v / cmv\text{ / cm}v / cm on the yyy-axis against u / cmu\text{ / cm}u / cm on the xxx-axis.
The student draws a straight line on the graph connecting the coordinates (25.0,25.0) cm(25.0, 25.0)\text{ cm}(25.0,25.0) cm and (45.0,45.0) cm(45.0, 45.0)\text{ cm}(45.0,45.0) cm. State the equation of this line.
The straight line intersects the experimental curved graph at the point where u1=34.8 cmu_1 = 34.8\text{ cm}u1=34.8 cm and v1=34.8 cmv_1 = 34.8\text{ cm}v1=34.8 cm. Calculate the focal length fff of the lens using the equation:
f=u1+v14 f = \frac{u_1 + v_1}{4} f=4u1+v1By substituting u=vu = vu=v into the thin lens formula:
1f=1u+1v \frac{1}{f} = \frac{1}{u} + \frac{1}{v} f1=u1+v1show that the equation f=u1+v14f = \frac{u_1 + v_1}{4}f=4u1+v1 is mathematically correct for the intersection point where u1=v1u_1 = v_1u1=v1.
56 exam-style questions on CIE IGCSE Physics 3.2.3a Converging and diverging lenses. Each one has a worked solution and a mark scheme showing where the marks go.