A physics class is investigating the magnification produced by a converging lens. An illuminated object of height h0=3.0 cmh_0 = 3.0\text{ cm}h0=3.0 cm is set up. The distance uuu between the illuminated object and the lens is varied, and for each distance, the screen is adjusted until a sharp image of height hIh_{\text{I}}hI is formed. Measurements are recorded in Table 3.1. Table 3.1: | u/cmu / \text{cm}u/cm | hI/cmh_{\text{I}} / \text{cm}hI/cm | S=h0hIS = \frac{h_0}{h_{\text{I}}}S=hIh0 | | :---: | :---: | :---: | | 40.040.040.0 | 3.03.03.0 | | | 45.045.045.0 | 2.42.42.4 | | | 50.050.050.0 | 2.02.02.0 | | | 55.055.055.0 | 1.71.71.7 | | | 60.060.060.0 | 1.51.51.5 | | | 65.065.065.0 | 1.31.31.3 | | | 70.070.070.0 | 1.21.21.2 | |
Calculate the values of SSS for each of the distances uuu, rounding them to one decimal place, to complete Table 3.1.
A graph of SSS (on the yyy-axis) vs u/cmu / \text{cm}u/cm (on the xxx-axis) is plotted, yielding a straight line of best fit.
Determine the gradient GGG of this line using the two extreme points of the data: (40.0,1.0)(40.0, 1.0)(40.0,1.0) and (70.0,2.5)(70.0, 2.5)(70.0,2.5).
Calculate the focal length fff of the lens, where:
f=1G f = \frac{1}{G} f=G156 exam-style questions on CIE IGCSE Physics 3.2.3a Converging and diverging lenses. Each one has a worked solution and a mark scheme showing where the marks go.