Define specific latent heat of fusion.
A beaker contains 400 cm3400\text{ cm}^3400 cm3 of water at a temperature of 8.0∘C8.0^\circ\text{C}8.0∘C. The beaker of water is placed in a freezer for several hours. When the beaker is removed from the freezer, it contains ice at a temperature of −15.0∘C-15.0^\circ\text{C}−15.0∘C. The density of water is 1000 kg/m31000\text{ kg/m}^31000 kg/m3.
Calculate the mass of water in the beaker when it is placed in the freezer.
The specific heat capacity of water is 4200 J/(kg ∘C)4200\text{ J/(kg }^\circ\text{C)}4200 J/(kg ∘C). The specific heat capacity of ice is 2100 J/(kg ∘C)2100\text{ J/(kg }^\circ\text{C)}2100 J/(kg ∘C). The specific latent heat of fusion of water is 3.3×105 J/kg3.3 \times 10^5\text{ J/kg}3.3×105 J/kg.
Calculate the total thermal energy released as the water cools from 8.0∘C8.0^\circ\text{C}8.0∘C to ice at −15.0∘C-15.0^\circ\text{C}−15.0∘C.
528 exam-style questions on CIE IGCSE Physics 2.2 Thermal properties and temperature, covering 2.2.1 Thermal expansion of solids, liquids and gases, 2.2.2a Internal energy and temperature, 2.2.2b Specific heat capacity, 2.2.3a Melting, boiling, condensation and solidification, 2.2.3b Evaporation, and 2.2.3c Cooling by evaporation. Each one has a worked solution and a mark scheme showing where the marks go.