An object of mass m m\,m with specific heat capacity c c\,c absorbs thermal energy ΔE \Delta E\,ΔE without changing its state. Which of the following expressions correctly gives the temperature rise ΔT \Delta T\,ΔT of the object?
ΔT=ΔEmc\Delta T = \frac{\Delta E}{m c}ΔT=mcΔE
ΔT=mcΔE\Delta T = \frac{m c}{\Delta E}ΔT=ΔEmc
ΔT=ΔEcm\Delta T = \frac{\Delta E c}{m}ΔT=mΔEc
ΔT=ΔEmc\Delta T = \frac{\Delta E m}{c}ΔT=cΔEm
528 exam-style questions on CIE IGCSE Physics 2.2 Thermal properties and temperature, covering 2.2.1 Thermal expansion of solids, liquids and gases, 2.2.2a Internal energy and temperature, 2.2.2b Specific heat capacity, 2.2.3a Melting, boiling, condensation and solidification, 2.2.3b Evaporation, and 2.2.3c Cooling by evaporation. Each one has a worked solution and a mark scheme showing where the marks go.