The table below shows the melting points and boiling points of Substance X and Substance Y:
SubstanceMelting PointBoiling PointSubstance X15∘C140∘CSubstance Y−10∘C65∘C \begin{array}{|c|c|c|} \hline \text{Substance} & \text{Melting Point} & \text{Boiling Point} \\ \hline \text{Substance X} & 15^\circ\text{C} & 140^\circ\text{C} \\ \hline \text{Substance Y} & -10^\circ\text{C} & 65^\circ\text{C} \\ \hline \end{array} SubstanceSubstance XSubstance YMelting Point15∘C−10∘CBoiling Point140∘C65∘CAt which temperature will both Substance X and Substance Y be in the liquid state?
0∘C0^\circ\text{C}0∘C
10∘C10^\circ\text{C}10∘C
35∘C35^\circ\text{C}35∘C
80∘C80^\circ\text{C}80∘C
528 exam-style questions on CIE IGCSE Physics 2.2 Thermal properties and temperature, covering 2.2.1 Thermal expansion of solids, liquids and gases, 2.2.2a Internal energy and temperature, 2.2.2b Specific heat capacity, 2.2.3a Melting, boiling, condensation and solidification, 2.2.3b Evaporation, and 2.2.3c Cooling by evaporation. Each one has a worked solution and a mark scheme showing where the marks go.