An experiment is conducted to determine the specific heat capacity c c\,c of an insulated metal block of mass m m\,m using an electric heater.
The heater is connected to a power supply providing a potential difference V V\,V and a current I I\,I for a time duration ttt. The thermometer measurements show that the temperature of the metal block increases by Δθ\Delta \thetaΔθ.
Assuming there is no heat loss to the surroundings, which equation correctly gives the specific heat capacity c c\,c of the metal?
c=VItmΔθc = \frac{V I}{t m \Delta \theta}c=tmΔθVI
c=VItmΔθc = \frac{V I t}{m \Delta \theta}c=mΔθVIt
c=mΔθVItc = \frac{m \Delta \theta}{V I t}c=VItmΔθ
c=tmΔθVIc = \frac{t m \Delta \theta}{V I}c=VItmΔθ
528 exam-style questions on CIE IGCSE Physics 2.2 Thermal properties and temperature, covering 2.2.1 Thermal expansion of solids, liquids and gases, 2.2.2a Internal energy and temperature, 2.2.2b Specific heat capacity, 2.2.3a Melting, boiling, condensation and solidification, 2.2.3b Evaporation, and 2.2.3c Cooling by evaporation. Each one has a worked solution and a mark scheme showing where the marks go.