An ideal transformer has NpN_{\text{p}}Np turns on its primary coil and NsN_{\text{s}}Ns turns on its secondary coil. The current in the primary coil is IpI_{\text{p}}Ip and the current in the secondary coil is IsI_{\text{s}}Is.
What is the relationship between these four quantities?
IpIs=NpNs\frac{I_{\text{p}}}{I_{\text{s}}} = \frac{N_{\text{p}}}{N_{\text{s}}}IsIp=NsNp
IpIs=NsNp\frac{I_{\text{p}}}{I_{\text{s}}} = \frac{N_{\text{s}}}{N_{\text{p}}}IsIp=NpNs
Ip×Is=Np×NsI_{\text{p}} \times I_{\text{s}} = N_{\text{p}} \times N_{\text{s}}Ip×Is=Np×Ns
IpIs=Np×Ns\frac{I_{\text{p}}}{I_{\text{s}}} = N_{\text{p}} \times N_{\text{s}}IsIp=Np×Ns
136 exam-style questions on CIE IGCSE Physics 4.5.6a Construction and operation of a transformer. Each one has a worked solution and a mark scheme showing where the marks go.