How many protons are in the nucleus of an atom of 88226Ra^{226}_{88}\text{Ra}88226Ra?
How many neutrons are in the nucleus of an atom of 88226Ra^{226}_{88}\text{Ra}88226Ra?
How many electrons are in a neutral atom of 88226Ra^{226}_{88}\text{Ra}88226Ra?
Where in the atom are these electrons to be found?
When a nucleus of 88226Ra^{226}_{88}\text{Ra}88226Ra decays by emitting an alpha-particle, it becomes a nucleus of radon (Rn\text{Rn}Rn).
The equation below represents this process:
88226Ra→YXRn+24α ^{226}_{88}\text{Ra} \rightarrow ^{X}_{Y}\text{Rn} + ^4_2\alpha 88226Ra→YXRn+24αDeduce the values of XXX and YYY.
284 exam-style questions on CIE IGCSE Physics 5.1 The nuclear model of the atom, covering 5.1.1a Structure of the atom and ions, 5.1.1b Alpha-particle scattering, 5.1.2a Composition of the nucleus and isotopes, 5.1.2b Proton number, nucleon number and nuclide notation, and 5.1.2c Nuclear fission and nuclear fusion. Each one has a worked solution and a mark scheme showing where the marks go.