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2.2.2a Internal energy and temperature

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Question 26

A student investigates some thermal properties of dry soil and water by conducting two experiments in a laboratory.

a.

The student starts with dry soil in a beaker. Water of volume 100 cm3 is heated and added to the soil.

  • Initial temperature of the dry soil (room temperature), θS=21.0∘C\theta_{\text{S}} = 21.0^\circ\text{C}θS​=21.0∘C
  • Temperature of the hot water supplier, θH1=85.0∘C\theta_{\text{H1}} = 85.0^\circ\text{C}θH1​=85.0∘C
  • Highest temperature of the soil-water mixture, θM1=49.0∘C\theta_{\text{M1}} = 49.0^\circ\text{C}θM1​=49.0∘C

(i) Calculate the rise in temperature θR1\theta_{\text{R1}}θR1​ of the soil, using the equation:

θR1=θM1−θS \theta_{\text{R1}} = \theta_{\text{M1}} - \theta_{\text{S}} θR1​=θM1​−θS​

(ii) Calculate the fall in temperature θF1\theta_{\text{F1}}θF1​ of the hot water, using the equation:

θF1=θH1−θM1 \theta_{\text{F1}} = \theta_{\text{H1}} - \theta_{\text{M1}} θF1​=θH1​−θM1​

(iii) Calculate the ratio S S\,S using the equation:

S=θR1θF1 S = \frac{\theta_{\text{R1}}}{\theta_{\text{F1}}} S=θF1​θR1​​
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b.

The beaker now contains 100 cm3 of cold water at room temperature. Another volume of 100 cm3 of hot water is heated and added to the cold water.

  • Initial temperature of the cold water (room temperature), θS=21.0∘C\theta_{\text{S}} = 21.0^\circ\text{C}θS​=21.0∘C
  • Temperature of this new hot water supplied, θH2=83.0∘C\theta_{\text{H2}} = 83.0^\circ\text{C}θH2​=83.0∘C
  • Highest temperature of the water-water mixture, θM2=50.0∘C\theta_{\text{M2}} = 50.0^\circ\text{C}θM2​=50.0∘C

(i) Calculate the rise in temperature θR2\theta_{\text{R2}}θR2​ of the cold water, using the equation:

θR2=θM2−θS \theta_{\text{R2}} = \theta_{\text{M2}} - \theta_{\text{S}} θR2​=θM2​−θS​

(ii) Calculate the fall in temperature θF2\theta_{\text{F2}}θF2​ of the hot water, using the equation:

θF2=θH2−θM2 \theta_{\text{F2}} = \theta_{\text{H2}} - \theta_{\text{M2}} θF2​=θH2​−θM2​

(iii) Calculate the ratio W W\,W using the equation:

W=θR2θF2 W = \frac{\theta_{\text{R2}}}{\theta_{\text{F2}}} W=θF2​θR2​​
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c.

Comparison and Control

The student predicts that S S\,S should be equal to 0.9×W0.9 \times W0.9×W. State whether these experimental results support this prediction. Justify your answer by comparing the values with reference to experimental accuracy (where results within 10% of each other are considered to support the prediction).

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d.

Suggest two temperatures that it would be sensible to keep constant when carrying out this investigation to ensure a fair comparison.

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Markscheme

2.2.2a Internal energy and temperature Questions

  1. IGCSE
  2. /Physics
  3. /2.2.2a Internal energy and temperature

119 exam-style questions on CIE IGCSE Physics 2.2.2a Internal energy and temperature. Each one has a worked solution and a mark scheme showing where the marks go.

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