A small toy drone is flying vertically downwards towards a flat, horizontal mirror on the floor. At a particular instant, the drone is at a height of 2.5 m above the mirror and is descending at a speed of 3.0 m/s.
What is the distance between the drone and its virtual image, and what is the speed of the image relative to the mirror?
Distance =2.5 m= 2.5\text{ m}=2.5 m; Speed =3.0 m/s= 3.0\text{ m/s}=3.0 m/s
Distance =2.5 m= 2.5\text{ m}=2.5 m; Speed =6.0 m/s= 6.0\text{ m/s}=6.0 m/s
Distance =5.0 m= 5.0\text{ m}=5.0 m; Speed =3.0 m/s= 3.0\text{ m/s}=3.0 m/s
Distance =5.0 m= 5.0\text{ m}=5.0 m; Speed =6.0 m/s= 6.0\text{ m/s}=6.0 m/s
48 exam-style questions on CIE IGCSE Physics 3.2.1a Reflection of light. Each one has a worked solution and a mark scheme showing where the marks go.