Lead, Pb, has a proton number equal to 82 and a nucleon number equal to 210.
Lead changes into bismuth, Bi, by emitting a β\betaβ-particle.
Which equation represents this decay?
21082Pb→21083Bi+0−1β{}^{82}_{210}\text{Pb} \to {}^{83}_{210}\text{Bi} + {}^{-1}_{0}\beta21082Pb→21083Bi+0−1β
21082Pb+0−1β→21083Bi{}^{82}_{210}\text{Pb} + {}^{-1}_{0}\beta \to {}^{83}_{210}\text{Bi}21082Pb+0−1β→21083Bi
82210Pb→83210Bi+−10β{}^{210}_{82}\text{Pb} \to {}^{210}_{83}\text{Bi} + {}^{0}_{-1}\beta82210Pb→83210Bi+−10β
82210Pb+−10β→83210Bi{}^{210}_{82}\text{Pb} + {}^{0}_{-1}\beta \to {}^{210}_{83}\text{Bi}82210Pb+−10β→83210Bi
484 exam-style questions on CIE IGCSE Physics 5.2 Radioactivity, covering 5.2.1 Background radiation and measuring count rate, 5.2.2a Alpha, beta and gamma emission, 5.2.2b Deflection and ionising effects of nuclear radiation, 5.2.3a Radioactive decay, 5.2.3b Effects of decay on the nucleus and decay equations, 5.2.4a Half-life, 5.2.4b Choosing isotopes for applications, and 5.2.5 Effects of ionising radiation and safety precautions. Each one has a worked solution and a mark scheme showing where the marks go.