Radium-226 decays by the emission of an α\alphaα-particle.
Which equation represents the decay of a radium-226 nucleus?
88226Ra→89226Rn+ −10α^{226}_{88}\text{Ra} \to ^{226}_{89}\text{Rn} + \ ^{0}_{-1}\alpha88226Ra→89226Rn+ −10α
88226Ra→86222Rn+ 24α^{226}_{88}\text{Ra} \to ^{222}_{86}\text{Rn} + \ ^{4}_{2}\alpha88226Ra→86222Rn+ 24α
88226Ra→86222Rn+ 42α^{226}_{88}\text{Ra} \to ^{222}_{86}\text{Rn} + \ ^{2}_{4}\alpha88226Ra→86222Rn+ 42α
88226Ra→90230Rn+ 24α^{226}_{88}\text{Ra} \to ^{230}_{90}\text{Rn} + \ ^{4}_{2}\alpha88226Ra→90230Rn+ 24α
484 exam-style questions on CIE IGCSE Physics 5.2 Radioactivity, covering 5.2.1 Background radiation and measuring count rate, 5.2.2a Alpha, beta and gamma emission, 5.2.2b Deflection and ionising effects of nuclear radiation, 5.2.3a Radioactive decay, 5.2.3b Effects of decay on the nucleus and decay equations, 5.2.4a Half-life, 5.2.4b Choosing isotopes for applications, and 5.2.5 Effects of ionising radiation and safety precautions. Each one has a worked solution and a mark scheme showing where the marks go.