Radium-226 decays by the emission of an α\alphaα-particle.
Which equation represents the decay of a radium-226 nucleus?
88226Ra→89226Rn+ −10α^{226}_{88}\text{Ra} \to ^{226}_{89}\text{Rn} + \ ^{0}_{-1}\alpha88226Ra→89226Rn+ −10α
88226Ra→86222Rn+ 24α^{226}_{88}\text{Ra} \to ^{222}_{86}\text{Rn} + \ ^{4}_{2}\alpha88226Ra→86222Rn+ 24α
88226Ra→86222Rn+ 42α^{226}_{88}\text{Ra} \to ^{222}_{86}\text{Rn} + \ ^{2}_{4}\alpha88226Ra→86222Rn+ 42α
88226Ra→90230Rn+ 24α^{226}_{88}\text{Ra} \to ^{230}_{90}\text{Rn} + \ ^{4}_{2}\alpha88226Ra→90230Rn+ 24α
120 exam-style questions on CIE IGCSE Physics 5.2.3a Radioactive decay. Each one has a worked solution and a mark scheme showing where the marks go.