The radioactive nucleus 82210Pb^{210}_{82}\text{Pb}82210Pb decays to another nucleus by the emission of a β\betaβ-particle. What is the proton number and what is the nucleon number of the nucleus formed by this decay?
Proton number: 808080, Nucleon number: 206206206
Proton number: 808080, Nucleon number: 210210210
Proton number: 838383, Nucleon number: 210210210
Proton number: 838383, Nucleon number: 212212212
120 exam-style questions on CIE IGCSE Physics 5.2.3a Radioactive decay. Each one has a worked solution and a mark scheme showing where the marks go.