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5.2.3a Radioactive decay

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Question 25

Radium-226 decays to radon-222 according to the following equation:

88226Ra→86222Rn+emitted particle {}^{226}_{88}\text{Ra} \rightarrow {}^{222}_{86}\text{Rn} + \text{emitted particle} 88226​Ra→86222​Rn+emitted particle

What is the emitted particle?

A

α\alphaα-particle

B

β\betaβ-particle

C

neutron

D

proton

Markscheme

5.2.3a Radioactive decay Questions

  1. IGCSE
  2. /Physics
  3. /5.2.3a Radioactive decay

120 exam-style questions on CIE IGCSE Physics 5.2.3a Radioactive decay. Each one has a worked solution and a mark scheme showing where the marks go.

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