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5.2.3a Radioactive decay

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Question 3

Lead, Pb, has a proton number equal to 82 and a nucleon number equal to 210.

Lead changes into bismuth, Bi, by emitting a β\betaβ-particle.

Which equation represents this decay?

A

21082Pb→21083Bi+0−1β{}^{82}_{210}\text{Pb} \to {}^{83}_{210}\text{Bi} + {}^{-1}_{0}\beta21082​Pb→21083​Bi+0−1​β

B

21082Pb+0−1β→21083Bi{}^{82}_{210}\text{Pb} + {}^{-1}_{0}\beta \to {}^{83}_{210}\text{Bi}21082​Pb+0−1​β→21083​Bi

C

82210Pb→83210Bi+−10β{}^{210}_{82}\text{Pb} \to {}^{210}_{83}\text{Bi} + {}^{0}_{-1}\beta82210​Pb→83210​Bi+−10​β

D

82210Pb+−10β→83210Bi{}^{210}_{82}\text{Pb} + {}^{0}_{-1}\beta \to {}^{210}_{83}\text{Bi}82210​Pb+−10​β→83210​Bi

Markscheme

5.2.3a Radioactive decay Questions

  1. IGCSE
  2. /Physics
  3. /5.2.3a Radioactive decay

120 exam-style questions on CIE IGCSE Physics 5.2.3a Radioactive decay. Each one has a worked solution and a mark scheme showing where the marks go.

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