Lead-210 is a radioactive isotope of lead that emits β\betaβ-particles as it decays. The nuclear equation below shows this decay.
82210Pb→ baX+ −10e \mathrm{^{210}_{82}Pb \rightarrow \,^a_b X + \,^0_{-1}e} 82210Pb→baX+−10eCalculate:
(i) the value of aaa,
a=………………………………… a = \text{\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots} a=…………………………………(ii) the value of bbb.
b=………………………………… b = \text{\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots\dots} b=…………………………………(i) Identify the element from the list below that is produced by this decay:
| Element | Proton number |
|---|---|
| mercury | 80 |
| thallium | 81 |
| lead | 82 |
| bismuth | 83 |
| polonium | 84 |
| astatine | 85 |
| radon | 86 |
(ii) The isotope baX\mathrm{^a_b X}baX is also radioactive and undergoes β\betaβ-decay. State the name of the element that is produced by this decay.
Three nuclei are represented as:
53131P54131Q53132R \mathrm{^{131}_{53}P \quad ^{131}_{54}Q \quad ^{132}_{53}R} 53131P54131Q53132RState and explain which nuclei are isotopes of the same element.
120 exam-style questions on CIE IGCSE Physics 5.2.3a Radioactive decay. Each one has a worked solution and a mark scheme showing where the marks go.