The chemical symbol for phosphorus is P\text{P}P. The equation represents the radioactive decay of phosphorus-32 to sulfur-32 (S\text{S}S).
1532P→x32S+−1ye \mathrm{^{32}_{15}P \rightarrow ^{32}_{x}S + ^{y}_{-1}e} 1532P→x32S+−1yeWhat are the numbers x x\,x and yyy?
x=14x = 14x=14, y=0y = 0y=0
x=14x = 14x=14, y=1y = 1y=1
x=16x = 16x=16, y=0y = 0y=0
x=16x = 16x=16, y=1y = 1y=1
120 exam-style questions on CIE IGCSE Physics 5.2.3a Radioactive decay. Each one has a worked solution and a mark scheme showing where the marks go.