Radioactive carbon-11 decays into boron-11 by emitting a positron (β+\beta^+β+-particle). The equation below represents the decay.
P11C→511B+Q0β {}^{11}_{P}\text{C} \rightarrow {}^{11}_{5}\text{B} + {}^{0}_{Q}\beta P11C→511B+Q0βWhat are the values of P P\,P and QQQ?
P=6P = 6P=6, Q=1Q = 1Q=1
P=6P = 6P=6, Q=−1Q = -1Q=−1
P=4P = 4P=4, Q=1Q = 1Q=1
P=4P = 4P=4, Q=−1Q = -1Q=−1
120 exam-style questions on CIE IGCSE Physics 5.2.3a Radioactive decay. Each one has a worked solution and a mark scheme showing where the marks go.