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5.2.3a Radioactive decay

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Question 86

Phosphorus-32 has a proton number (ZZZ) of 15 and a nucleon number (AAA) of 32.

Sulfur-32 has a proton number of 16 and a nucleon number of 32.

Phosphorus-32 emits a β\betaβ-particle to form sulfur-32.

Which nuclide equation describes this process?

A

1532P→1632S+10β^{32}_{15}\text{P} \rightarrow {^{32}_{16}\text{S}} + {^{0}_{1}\beta}1532​P→1632​S+10​β

B

3215P→3216S+01β^{15}_{32}\text{P} \rightarrow {^{16}_{32}\text{S}} + {^{1}_{0}\beta}3215​P→3216​S+01​β

C

1532P→1632S+−10β^{32}_{15}\text{P} \rightarrow {^{32}_{16}\text{S}} + {^{0}_{-1}\beta}1532​P→1632​S+−10​β

D

3215P→3216S+0−1β^{15}_{32}\text{P} \rightarrow {^{16}_{32}\text{S}} + {^{-1}_{0}\beta}3215​P→3216​S+0−1​β

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5.2.3a Radioactive decay Questions

  1. IGCSE
  2. /Physics
  3. /5.2.3a Radioactive decay

120 exam-style questions on CIE IGCSE Physics 5.2.3a Radioactive decay. Each one has a worked solution and a mark scheme showing where the marks go.

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