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5.2.3a Radioactive decay

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Question 27

Polonium-218 is a radioactive isotope.

a.

The nuclide notation for polonium-218 is 84218Po^{218}_{84}\text{Po}84218​Po. Describe the composition of a neutral atom of polonium-218.

[3]
b.

A nucleus of polonium-218 decays to an isotope of lead (Pb\text{Pb}Pb) by emitting an alpha particle. Complete the nuclide equation for the decay of polonium-218.

84218Po→ ___ α+ ___ Pb ^{218}_{84}\text{Po} \rightarrow \text{ \_\_\_ }\alpha + \text{ \_\_\_ }\text{Pb} 84218​Po→ ___ α+ ___ Pb
[2]
c.

A detector of radiation is placed near a sample of polonium-218 and gives a reading of 960 counts/s960\text{ counts/s}960 counts/s. The half-life of polonium-218 is 3.0 minutes3.0\text{ minutes}3.0 minutes. Calculate the reading after 12.0 minutes12.0\text{ minutes}12.0 minutes. Ignore background radiation.

[2]
Markscheme

5.2.3a Radioactive decay Questions

  1. IGCSE
  2. /Physics
  3. /5.2.3a Radioactive decay

120 exam-style questions on CIE IGCSE Physics 5.2.3a Radioactive decay. Each one has a worked solution and a mark scheme showing where the marks go.

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