The nucleus of an isotope of aluminium (Al) absorbs an α\alphaα-particle. It then transitions into an isotope of phosphorus (P) and emits a particle y y\,y as shown in the nuclear equation below:
24He+1327Al→1530P+y {}^{4}_{2}\text{He} + {}^{27}_{13}\text{Al} \rightarrow {}^{30}_{15}\text{P} + y 24He+1327Al→1530P+yWhat is particle yyy?
proton
β−\beta^-β−-particle
neutron
γ\gammaγ-radiation
120 exam-style questions on CIE IGCSE Physics 5.2.3a Radioactive decay. Each one has a worked solution and a mark scheme showing where the marks go.