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1.7.4 Power

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Question 60

An electric motor is used to lift a cargo container of weight G G\,G to a storage platform at a height h h\,h using two different transport mechanisms:

  • Mechanism 1 (Vertical Crane): The crane lifts the container vertically. It takes 15 s to reach the platform. The useful work done against gravity is WWW, and the useful power developed is PPP.
  • Mechanism 2 (Incline Conveyor): The conveyor carries the same container up a ramp to the same platform. It takes 25 s to reach the platform.

Which row in the table correctly identifies the useful work done against gravity and the useful power developed by Mechanism 2?

Useful work done against gravity by Mechanism 2Useful power developed by Mechanism 2
Amore than WWWless than PPP
Bmore than WWWequal to PPP
Cequal to WWWless than PPP
Dequal to WWWequal to PPP
A

Useful work: more than WWW; Useful power: less than PPP

B

Useful work: more than WWW; Useful power: equal to PPP

C

Useful work: equal to WWW; Useful power: less than PPP

D

Useful work: equal to WWW; Useful power: equal to PPP

Markscheme

1.7.4 Power Questions

  1. IGCSE
  2. /Physics
  3. /1.7.4 Power

95 exam-style questions on CIE IGCSE Physics 1.7.4 Power. Each one has a worked solution and a mark scheme showing where the marks go.

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