Which equation correctly expresses the force exerted by an engine in terms of its constant power output, the distance moved in the direction of the force, and the time taken?
force=power×distance movedtime taken\text{force} = \frac{\text{power} \times \text{distance moved}}{\text{time taken}}force=time takenpower×distance moved
force=power×distance moved×time taken\text{force} = \text{power} \times \text{distance moved} \times \text{time taken}force=power×distance moved×time taken
force=power×time takendistance moved\text{force} = \frac{\text{power} \times \text{time taken}}{\text{distance moved}}force=distance movedpower×time taken
force=distance moved×time takenpower\text{force} = \frac{\text{distance moved} \times \text{time taken}}{\text{power}}force=powerdistance moved×time taken
95 exam-style questions on CIE IGCSE Physics 1.7.4 Power. Each one has a worked solution and a mark scheme showing where the marks go.