Define specific latent heat of fusion.
A beaker contains 400 cm3400\text{ cm}^3400 cm3 of water at a temperature of 8.0∘C8.0^\circ\text{C}8.0∘C. The beaker of water is placed in a freezer for several hours. When the beaker is removed from the freezer, it contains ice at a temperature of −15.0∘C-15.0^\circ\text{C}−15.0∘C. The density of water is 1000 kg/m31000\text{ kg/m}^31000 kg/m3.
Calculate the mass of water in the beaker when it is placed in the freezer.
The specific heat capacity of water is 4200 J/(kg ∘C)4200\text{ J/(kg }^\circ\text{C)}4200 J/(kg ∘C). The specific heat capacity of ice is 2100 J/(kg ∘C)2100\text{ J/(kg }^\circ\text{C)}2100 J/(kg ∘C). The specific latent heat of fusion of water is 3.3×105 J/kg3.3 \times 10^5\text{ J/kg}3.3×105 J/kg.
Calculate the total thermal energy released as the water cools from 8.0∘C8.0^\circ\text{C}8.0∘C to ice at −15.0∘C-15.0^\circ\text{C}−15.0∘C.
313 exam-style questions on CIE IGCSE Physics 2.2.3a Melting, boiling, condensation and solidification. Each one has a worked solution and a mark scheme showing where the marks go.