The table below shows the melting points and boiling points of Substance X and Substance Y:
SubstanceMelting PointBoiling PointSubstance X15∘C140∘CSubstance Y−10∘C65∘C \begin{array}{|c|c|c|} \hline \text{Substance} & \text{Melting Point} & \text{Boiling Point} \\ \hline \text{Substance X} & 15^\circ\text{C} & 140^\circ\text{C} \\ \hline \text{Substance Y} & -10^\circ\text{C} & 65^\circ\text{C} \\ \hline \end{array} SubstanceSubstance XSubstance YMelting Point15∘C−10∘CBoiling Point140∘C65∘CAt which temperature will both Substance X and Substance Y be in the liquid state?
0∘C0^\circ\text{C}0∘C
10∘C10^\circ\text{C}10∘C
35∘C35^\circ\text{C}35∘C
80∘C80^\circ\text{C}80∘C
313 exam-style questions on CIE IGCSE Physics 2.2.3a Melting, boiling, condensation and solidification. Each one has a worked solution and a mark scheme showing where the marks go.